Sunday, September 14, 2008
Ladislav Prokeš raises the question: how to win?
1.Re8-h7-e7 Rg6 followed 2 ... Fb3xe6 with invalidity or insured 1.Re8 Rg6-d7-h7-e7 2.e6 Fb2-a4 + followed 3.Rh7xg8 and finally on-e7 1.e6 blacks replicate Fb3xg8 1 ... and the fool should be able to control the promotion square, not ?
But no! 1.e6-e7! Fb3xg8 FB3-1 ... a4 + + 2.Re8-f8 - (2.Re8-d8? Rg6-f7 =) or 1 ... Rg6-f8-h7 2.Re8 + -) 2.Re8-f8 FG8 3.Fh6-g5-f7! + - not 3.Fh6-g7? Rg6-h7! 4.Rf8xf7 = and blacks are pat! Emilian Dobrescu
, meanwhile, wants to demonstrate that a pawn is worth one in the sixth round. Is true?
Ladislav Prokeš raises the question: how to win?
1.Re8-h7-e7 Rg6 followed 2 ... Fb3xe6 with invalidity or insured 1.Re8 Rg6-d7-h7-e7 2.e6 Fb2-a4 + followed 3.Rh7xg8 and finally on-e7 1.e6 blacks replicate Fb3xg8 1 ... and the fool should be able to control the promotion square, not ?
But no! 1.e6-e7! Fb3xg8 FB3-1 ... a4 + + 2.Re8-f8 - (2.Re8-d8? Rg6-f7 =) or 1 ... Rg6-f8-h7 2.Re8 + -) 2.Re8-f8 FG8 3.Fh6-g5-f7! + - not 3.Fh6-g7? Rg6-h7! 4.Rf8xf7 = and blacks are pat! Emilian Dobrescu
, meanwhile, wants to demonstrate that a pawn is worth one in the sixth round. Is true?
The idea is simple but rather tedious solution. For the full solution with variants, see solution in JavaScript . Extraordinarily, all shots are unique and rather unexpected conclusion.
1.d6-d7! TF7-f4 2.d4-d5! TF4-d4 3.Rd8-c8! Td4xd5 4.b6 5.b7 Td5xd7-b7-b8: C +! RA6-b6 6.Cb8xd7 It's not quite finished ... RB6-6 ... c6 7.Cd7-e5 +! Whites earn, the rider will find refuge in b2, the white king had no difficulty in capturing the pawn a5.
archives ... and comments to Patrick Old
1.d6-d7! TF7-f4 2.d4-d5! TF4-d4 3.Rd8-c8! Td4xd5 4.b6 5.b7 Td5xd7-b7-b8: C +! RA6-b6 6.Cb8xd7 It's not quite finished ... RB6-6 ... c6 7.Cd7-e5 +! Whites earn, the rider will find refuge in b2, the white king had no difficulty in capturing the pawn a5.
archives ... and comments to Patrick Old
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